Square EFGH stretches vertically by a factor of 2.5 to create square E′F′G′H′. The square stretches with respect to the x-axis. If point H is located at (-2, 0), what are the coordinates of H′ ?

A. (-5, 0)

B. (-2, 0)

C. (0.5, 0)

D. (-2, 2.5)

Question

Square EFGH stretches vertically by a factor of 2.5 to create square E′F′G′H′. The square stretches with respect to the x-axis. If point H is located at (-2, 0), what are the coordinates of H′ ?

A. (-5, 0)

B. (-2, 0)

C. (0.5, 0)

D. (-2, 2.5)

_malice_ · Answer

;-;

_malice_ · Answer

@mattfort3212  @Fruitcakeninja

aakashtomar · Answer

Is it given that the origin lies on the center of one side?

_malice_ · Answer

no idea

_malice_ · Answer

what I posted above is all it shows me for this problem.

_malice_ · Answer

It should also be noted that I have no idea what Im doing :)

aakashtomar · Answer

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Now if you stretch GH by a factor of 2.5 it becomes 5. As it is initially 2. Thus the coordinates of H should be (-5,0).