Question

An acute angle θ is in a right triangle with sin θ = five sixths. What is the value of cot θ?

Answer 1

@agent0smith

Answer 2

@sammixboo

Answer 3

@jigglypuff314

Answer 4

@mayankdevnani

Answer 5

Hmm. First take out cos of theta by the eqn cosx= (√1-sin^2x) Then use cosx/sinx = cotx

Answer 6

I've tried that but I always mess it up

Answer 7

I kept getting 5/6 but that's not an answer
Answer:
five divided by the square root of eleven
six divided by the square root of eleven
square root of eleven divided by five
square root of eleven divided by six

Answer 8

Then try making a right triangle.

Remember sin theta = opposite/hypotenuse

you have sin theta = 5/6

Answer 9

..I'm confused I've tried

Answer 10

sin theta = opposite/hypotenuse

you have sin theta = 5/6

So draw a right triangle with an angle theta. Tell me what the opposite is, and what the hypotenuse is, based on what I wrote above.

Answer 11

I don't know this, you can go haha

Answer 12

I'll make it even easier

sin theta = opposite/hypotenuse
sin theta = 5 / 6

Tell me what the opposite is, and what the hypotenuse is.

Answer 13

opposite is 5 and hypotenuse is 6

Answer 14

So make a triangle like this http://www.technologyuk.net/mathematics/trigonometry/images/trigonometry_0018.gif

Answer 15

Alright

Answer 16

I did that

Answer 17

the next step is use pythagoras to find the 3rd side.

Answer 18

I'm so confused with this whole thing

Answer 19

do you know how to do that ?
\[ a^2 + b^2 = c^2 \]
where a and b are the "legs" and c is the hypotenuse

Answer 20

Find b

Answer 21

Alright, I did that

Answer 22

Is it A?

Answer 23

Show work. I'll check your work. I won't check whether it's A or not.

Answer 24

@phi

Answer 25

Don't tag someone else to get them to check your answer (which could very easily be a guess)

Show work and prove to us that you did it correct.