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if sin(theta)sec(theta) = -1 and theta lies in second quadrant ,find sin theta and sec theta
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http://tutorial.math.lamar.edu/pdf/Trig_Cheat_Sheet.pdf look at the `Reciprocal Identities` section (page 2) and you'll see that \[\Large \sec(\theta) = \frac{1}{\cos(\theta)}\]
also look in the `Tangent and Cotangent Identities` section just above the reciprocal section and you'll see \[\Large \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}\]
Doing all this will hopefully convince you that \[\Large \sin(\theta)\sec(\theta) = -1\] is the same as \[\Large \tan(\theta) = -1\]
okay, what next?
Then tan theta = -1/1
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Draw an xy axis |dw:1466141699502:dw|
we're in quadrant 2 now |dw:1466141729147:dw|
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