Given that f(x) = 2x + 1 and g(x) = the quantity of 3x minus 1, divided by 2, solve for g(f(3)) A) 5 B) 7 C) 9 D) 10
Please help @jigglypuff314 @agent0smith @YanaSidlinskiy
I helped you with a similar one yesterday. Try using that example and putting these numbers as I did yesterday
I forgot how you laid it out lol, do you mind giving me the format and I'll plug in the numbers?
Hold on:)
KK tyy :)
Refer to that: http://openstudy.com/users/george.g101#/updates/5762fbc2e4b02b7e8db80aed
Ok so \[g(x)= 3(3)-1 \over 2\]
g(x)=\[g(x)= 5/2\]
Wait no 8/2= g(x)= 4
SOS @agent0smith lol
Keep in mind you're finding g(f(3)); you need the INSIDE function first. Not the outside one.
Sorry I'm really confused math is my weak spot =/
g( f(3) ) ^find f(3) first.
f(3)= 2(3)+1? = f(3)= 7
Good now find g( f(3) )
g(3)= 3(3)-1 over 2. = 8/2= g(3)=4?
I'm stuck now :/
You're finding g( f(3) ) What was f(3)?
7
So then replace f(3) with 7. You aren't finding g(3). You're finding g( f(3) )
Wait I just worked it out the answer is '9' right?
Idk, show your work.
Intelligence, I just summited it it I'll tell you if I was right. Thanks for your help:)
No... show your work.
I don't care if the answer is right or not. I'm saying show your work because if the work is right, the answer will be.
And on a test, teachers don't give full credit for just an answer. Work needs to be shown.
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