Question

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What is ^3√-125

Answer 1

@sammixboo please help me

Answer 2

Are you dealing with imaginary numbers right now in your work?

Answer 3

I'm not sure what that means, but im just dealing with irrational numbers.

Answer 4

And did you mean to have the carrot in that questions. (the ^ symbol)

Answer 5

Well in order to take the root of a negative number, you use imaginary numbers, or i.

Answer 6

Ah. the three is the root for the square.

Answer 7

let me write it out

Answer 8

well, 125^(1/3) is 5*5*5

Answer 9

And because it is negative, you just put an i after the number, 5i

Answer 10

because the third root of 125 is 5.

Answer 11

Answer: 5i

Answer 12

i dont think i could put i in my fill in the blank

Answer 13

Does your question provide a link to look at the chapter your are doing work in? That will tell me if you are doing complex or just irrational. The only answer to this question has an i because of that negative number under the roof.

Answer 14

just irrational

Answer 15

@lapinblanc only even roots are imaginary. If the exponent is odd, then the root is real.

Answer 16

Since (-5)(-5)(-5) = -125

So the cube root of -125 is -5.

Answer 17

Silly me, because -5*-5*-5.

Answer 18

\(º-º)/

Answer 19

Thank you @agent0smith

Answer 20

When you take the root of something, your root tells you how many times it has to be repeated to remove it.
for example
\[\sqrt[2]{4}\]
Is the same thing as saying \[\sqrt[2]{2*2}\]
So the answer is 2.
In our case we have \[\sqrt[3]{-125}\] which is the same as \[\sqrt[3]{-5*-5*-5}\] so our answer is -5

Answer 21

\(\sqrt[\text{odd}]{-a}=-\sqrt[\text{odd}]{a}\)

Answer 22

Oh, i think i get it. :D So we just needed to find the number that would go in 3 times. I see. :)

Answer 23

Precisely.

Answer 24

Wow, simpler than i had thought

Answer 25

Thank you so much for you're help. :) It's really appreciated

Answer 26

^__^