Question

What is the product in simplest form? State any restrictions on the variable.

Answer 1

\[\frac{ y ^{2} }{ y-3 }.\frac{ y ^{2}-y-6 }{ y ^{2+1y} }\]

Answer 2

@sleepyjess pls help me

Answer 3

@wolf1728 pls help me

Answer 4

@ivettef365 pls help me

Answer 5

pls help me anyone

Answer 6

sorry, that's a little bit beyond my knowledge

Answer 7

@wolf1728 Thanks anyway :)

Answer 8

Lots of ways to start. I'd consider trying to factor the term y*2−y−6 and see if you can cancel anything.

Answer 9

is that supposed to be an exponent? \(\large y^{\color{red}{2+1y}}\)

Answer 10

yes always then you need working with fractions with unnknowed terms there are restrictions what will be the value of unknowed term for what value the denominator of fraction(s) will result equal zero - bc. you know that in case that the denominator of a fraction is equal zero so in this case the fraction will be undefined
hope this will help you making the restrictions for your exercise easy

Answer 11

@rebeccaxhawaii

Answer 12

\[\frac{ y+2 }{ y ^{y} }\]

Answer 13

y cannot equal 0.

Answer 14

@youngAbuDabbin
Would you please comment on @nincompoop 's question, namely
please doublecheck on the following in red:
\(\Huge \frac{ y ^{2} }{ y-3 }.\frac{ y ^{2}-y-6 }{ y ^\color{red}{2+1y} }\)
Would it be \(\color{green}{(2+1)y}\), \(\color{blue}{2+1}\), \(\color{purple}{2+y}\), \(\color{red}{2+1y}\), or simply \(\color{magenta}{y+2}\) without the exponentiation?

Answer 15

@Kinged, when you help someone, please keep in mind the OpenStudy Code of Conduct. Avoid jumping straight to an answer, especially when someone else is helping out already.

http://openstudy.com/code-of-conduct
Don't devalue the question/answer process!
Don't provide someone with just the answer - explain the process, and help guide them through understanding the problem.
Don't just provide the answer to a problem when someone else is in the middle of helping! But if you want to help, by all means, join in!

Answer 16

You just think of \[y ^{2+1y}\]as \[y ^{2} \times y ^{y}\]then you factor \[y ^{2}-y-6\]into \[(y+2)(y-3)\] and finally you simplify by cancellation.