Jake has a bag of 50 beads, of which some are red and the remaining are yellow. Jake randomly pulls out a bead from the bag, records the color, and replaces it in the bag. Jake has already recorded 9 red and 6 yellow beads. Based on the result, what is most likely the number of red beads in the bag?
Options 10 20 30 60
The total population is 50 beads in the bag. The estimated percentage of red beads is 9/15 since Jake pulled 9 red beads out of 15 (9+ 6) attempts in his sample. If B = event of picking a red bead with replacement, the estimated probability of picking a red bead is: P(B) = 3/5 = 0.6 That probability is the same for each bead Jake pulls out, because he replaces it each time. The best estimate of the number of blue beads in the bag is 50 x 0.6 = 30 red beads (with 15 green beads remaining)
:|
Options 10 20 30 60
nbm
It's 30 red beads.
nvm
k
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