Question

What is the discontinuity and zero of the function f(x) = the quantity of 2 x squared plus 5 x minus 12, all over x plus 4 ?

Discontinuity at (−4, −11), zero at ( three halves , 0)

Discontinuity at (−4, −11), zero at ( negative three halves , 0)

Discontinuity at (4, 5), zero at ( three halves , 0)

Discontinuity at (4, 5), zero at ( negative three halves , 0)

Answer 1

the x-coordinate of the discontinuity can be found by setting the denominator equal to 0

Answer 2

so, x = - 4?

Answer 3

yes, and can you write the equation using the equation tool or the draw tool so I can see it better?

Answer 4

@thesmartone

Answer 5

can you factor the numerator?

Answer 6

Yes, (2x - 3) • (x + 4).

Answer 7

now set each equal to 0

2x - 3 = 0
x +4 = 0

and those are the roots

Answer 8

roots are the same thing as zeroes or solutions or x-intercepts :)

Answer 9

Oh, okay, so where do they come in for the answer?

Answer 10

I don't understand how to get the answer. :(

Answer 11

2x - 3 = 0

what is x = ?

Answer 12

0?

Answer 13

no, add 3 to both sides and then divide by 2

Answer 14

Oh! \[\frac{ 3 }{ 2 }\]

Answer 15

So my answer is A. Discontinuity at (−4, −11), zero at ( three halves , 0) ???

Answer 16

@TheSmartOne Is that correct?

Answer 17

correct! ^-^

Answer 18

Thank you! (^̮^)