Question

find the sum of each finite series

Answer 1

\[\sum_{n=1}^{10}(3n-4)\]

Answer 2

what do you get when n = 1?

Answer 3

what do you get for n = 2?

.
.

what do you get for n = 10?

then add those numbers up. There is your sum

Answer 4

12?

Answer 5

where did that 12 come from?

Answer 6

\(\sum_{n=1}^{10}(3n-4)=3\sum_{n=1}^{10}n-\sum_{n=1}^{10}4=3\sum_{n=1}^{10}n-40\)

Answer 7

Might I recommend using the formula \[[n(a _{1} + a _{n})]\div2\]

Answer 8

Where n is the number of terms, a1 is the first term, and an is the last term.

Answer 9

right,or you can use the short cut like others just recommended.

(number of terms) (first term + last term)/2