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Whats the easiest way to solve for x here? 4sqrt(x)=(1/16)x^2
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\[4\sqrt{x}=\frac{ 1 }{ 16 }x^2\]
im doing this for integration to find the area between the curves, and it seems like completing the square for this is a really long process when added on top of the integration. I bet there's a trick to know the bounds faster
graphing?
wolfram alpha. Can't get faster than that lol
maybe factoring if you have to do it by hand \[4\sqrt{x}-\frac{1}{16}x^2=0\] \[\frac{ 1 }{ 16 }\sqrt{x}(64-x^\frac{3}{2})=0\] \[\sqrt{x}=0 \rightarrow x=0\] \[(64-x^\frac{3}{2})=0\rightarrow x=16\]
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I like that @peachpi I didnt think of that thank you. Wolfram Alpha is great but unfortunately I cant use it on the test :P
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