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Solve the equation: 6 = x+2/3
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\[6=\frac{x+2}{3}\] right?
yes
a) multiply both sides by 3 to get rid of the fraction, then b) subtract 2 from both sides
How would I multiply 3 on the fraction side?
cancel the 3, that is the whole point of multiplying by three, gets rid of the three in the denominator
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\[\frac{x+2}{3}\times 3=\frac{x+3}{\cancel3}\times \cancel 3=x+2\]
Oh ok, I see now
It then becomes 18 = x + 2 ?
yes
Then 16 = x
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yes
Ahh ok
Thanks :)
yw
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