WILL MEDAL AND FAN BEST ANSWER PLEASE! HURRY! How much work is accomplished when a force of 250 N pushes a box across the floor for a distance of 50 meters? A. 12,500 J B. 5 N C. 12,500 N D. 5 J
\[Work = Force*distance*\angle~betwn~applied~force~and~direction~of~motion\] \[W = FdCos(\phi)\] |dw:1467396430702:dw|
12,500? Idk how to figure out J or N either. I think J? because its power, and power is how much work is accomplish, I think?
Idk what N is tho
@Photon336
You have the right formula. remember we're talking about work the angle is 0 btw. you already know the applied force F and the distance in meters d.
all you have to do is plug it into the formula.
Hm.. Ok this is hard DX Sorry, my brain is a little below average, at least in science and math. The applied force is 250 N and the distance is 50 meters, and up there you put * so my mind put it as multiply, if not that idk what we're doing.
yeah don't worry. just tell me where you are confused
so do you know the definition of what work is?
I thought that we multiplied 250 and 50, so that equals 12,500. But how do I know if its J or N? Am I even doing it right?
yeah that's right but also make sure you keep track of your units.
remember in \[Work~W = Force*Distance = Newtons*Meters \]
so your units will be Newtons~meters which equal work
AKA Joules
Oh Does * equal multiplication?
yep
Oh okay
this means that we are applying a force over a distance
that's the definition of work
Why is It J (Joules?) and not N (Newtons?)
Joules = Newtons*meters
OOHH!! That makes so much more sense.
I understand this now. Thank you so much!
no problem
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