I just need to know the steps on how to solve this: If the area of a trapezoid is 40 cm squared, the height is 4 cm and the bottom base is 12 cm, what is the length of the top base?
|dw:1468377195550:dw|
Area of trapezoid \[\Large A = h*\frac{b_1+b_2}{2}\]
b1 and b2 are the parallel bases h is the height
My online teacher never taught me to divide the bases by 2
how about multiplying the sum by 0.5?
maybe your teacher gave you something like this? \[\Large A = h*0.5*(b_1+b_2)\]
My classes are online so I never interact with him. He just gives us questions and videos to watch but the videos don't really explain it. But i would just plug in what I already know right?
yes `If the area of a trapezoid is 40 cm squared, the height is 4 cm and the bottom base is 12 cm` A = 40 h = 4 b1 = x b2 = 12
40=4* b1+12/2 ??
\[\Large A = h*\frac{b_1+b_2}{2}\] \[\Large 40 = 4*\frac{x+12}{2}\] \[\Large 40 = 4*\frac{1}{2}*(x+12)\] \[\Large 40 = 2*(x+12)\] \[\Large 40 = 2x+24\] solve for x
x=8
correct
That was easier than I thought. I understood it more thank you
no problem
Join our real-time social learning platform and learn together with your friends!