Question

help me dad:
http://prntscr.com/bvcsn4
PLEASE! I NEED HELP!

Answer 1

@Mehek14 = dad

Answer 2

@Preetha @pooja195 @Jadeishere @ganeshie8

Answer 3

@zepdrix

Answer 4

@agent0smith

Answer 5

Just make the 'd' value some big-a.ss negative number, and the rest all small positive numbers.

Answer 6

@agent0smith d -1000, and the rest 1,2,3 ? XD

Answer 7

And I have to make 2 of them.

Answer 8

For the other, make it pretty much the same, but all positive.

Answer 9

So,
Part 1.)
a = 1, b = 2, c = 3, d = -1000
second one,
a = 1 b = 2 c = 3 d = 1000
?

Answer 10

Sure. I mean you can make it easier to solve by making nice numbers and such, but meh that's fine

Answer 11

Now part 2. How?

Answer 12

Get the square root by itself, the same way you'd get an x by itself. Add/subtract/divide etc on both sides.

Answer 13

Once you have the square root by itself, square both sides to get rid of it.

Answer 14

I dont know how to do that. I am really bad at square roots

Answer 15

"Get the square root by itself, the same way you'd get an x by itself. "

If you can get an x by itself in a regular equation, you can do the same here.

Answer 16

D - B - C?

Answer 17

Or, a\[\sqrt{x}\]= -1000 - 2 - 3?

Answer 18

It'd help a lot if you wrote out your equation here, with the equation editor

Answer 19

Ok, let me do that, \[a \sqrt{x} = -1000 - 2 - 3\]

Answer 20

There was a number inside the square root, so no.

Get the square root alone (do not touch anything inside it). Then square both sides.

Answer 21

How Im sorry D:

Answer 22

First step is to write it correctly
\[\large a \sqrt{x+b}+c = d\]Then get the square root by itself, the same way you'd get an x by itself in a simpler equation\[\large a \sqrt{x+b} = d-c \] \[\large \sqrt{x+b}= \frac{ d - c }{ a }\]Now you square both sides.

Answer 23

Once you square both sides, you just subtract b and you're done.

Answer 24

So
\[\sqrt{x^{2}} = \frac{ d-c }{ a } - b ^{2}\]

Answer 25

No, squaring cancels a square root entirely, leaving everything inside it unchanged\[\large \left( \sqrt{x+b}\right)^2= \left( \frac{ d - c }{ a } \right)^2\]
\[\large x+b= \left( \frac{ d - c }{ a } \right)^2\]

Answer 26

Thats the asnwer?

Answer 27

So do I replace the letters with numbers and solve? Or keep it that way?

Answer 28

Well you're supposed to get the actual solutions lol, so yes put in your numbers. And don't forget of course, you still need to subtract b to finish.

Answer 29

What is part 3?

Answer 30

Because if you show work correctly, at a certain point you'll have a square root equal to a negative - and that's never possible.

Answer 31

Part 2.)
Equation 1 is the extraneous solution.
1 _/x+2 + 3 = -1000
1_/x+2 = -1003
_/x+2 = -1003/1
X + 2 = -1003^2
X = -1005^2
Equation 2.
1 _/x + 2 + 3 = 1000
1_/x+2 = 997
_/x+2 = 998/1
X + 2 = 998/1^2
X = 996^2

Answer 32

correct?