Question

Help

Answer 1

Notice in the first equation we have the constant term -17
In the second equation, we have the constant term -102

Fill in the blank
-17 times ____________ = -102
what must go in the blank?

Answer 2

6 @jim_thompson5910

Answer 3

Now what

Answer 4

6 is correct

Answer 5

so what is going on is you'll multiply both sides of \(\Large 2x+3y = -17\) by 6 to get

\[\Large 2x+3y = -17\]
\[\Large 6*(2x+3y) = 6*(-17)\]
\[\Large 6*(2x)+6*(3y) = 6*(-17)\]
\[\Large 12x+18y = -102\]

Do you see what to do next?

Answer 6

Not really..

Answer 7

subtract 12x from both sides

Answer 8

\[\Large 12x+18y = -102\]
\[\Large 12x+18y-12x = -102-12x\]
\[\Large 18y = -12x-102\]

Answer 9

So is that the solution?

Answer 10

yes, just fill in the boxes with the coefficients you see in front of y and x

Answer 11

I get it thank you

Answer 12

no problem