Question

- Would anyone have the patience to help me through a simplex method Q?

Answer 1

no

Answer 2

This is the Q.

Answer 3

lol feel bad for you

Answer 4

why is no one helping this young man

Answer 5

Well this will probably take an hour, but we can at least talk about the initial setup

Answer 6

you are going to have 2 slack variables in this case and a total of three lines in the initial matrix

Answer 7

one line for the two constraints, and one line for the profit function

Answer 8

using s1 for the slack of the 1st restraint and s2 for the slack of the second restraint I get the initial matrix will be

Answer 9

Evoker, I can greatly reduce time. I've got it all setup etc

Answer 10

I only need help with the first part, arriving at the optimal solution

Answer 11

Ah sure, well if you can show me your work, we can discuss

Answer 12

Ok

Answer 13

Just a moment

Answer 14

https://youtu.be/gRgsT9BB5-8 has a good full example of a similar problem by the way

Answer 15

I am not bad with the method of Simplex, it's THIS PARTICULAR problem, I can't get right.

Answer 16

Ah ok

Answer 17

Drawing will be tough, let me attach pictures

Answer 18

Yeah probably easiest

Answer 19

Thank you so much btw

Answer 20

- How I set it up

Answer 21

Setup looks good

Answer 22

as well as first pivot point

Answer 23

- So, most negative number in Z is -4, so I did the ratios of Solution to the corresponding column?

Answer 24

So I need to turn 8 to a 1, and Zero the other 2, right?

Answer 25

Exactly

Answer 26

Heres the problem

Answer 27

Dividing R1 / 8 = Is ok yeah?

Answer 28

yeah

Answer 29

So, then making the others Zero...

Answer 30

Apologies for paper being bad

Answer 31

-R1+R2, and 4R1+R3

Answer 32

Could you take a picture with the previous step and this step so I can follow along

Answer 33

The last picture is a new page, but let me try

Answer 34

Both together...

Answer 35

x4 would then need to be made 1? Which will mean it'll ruin the x3 column when we do a new row operation?

Answer 36

ok one sec, look good for the zeroing

Answer 37

I agree one of the x4's needs to be made 1.

Answer 38

So via the ratio rule, dividing our solution by both X4 values, we choose the smaller, which is 12.5

Answer 39

So we need to make 4/8 = 1, but to do so, will mean destroying x3? lol

Answer 40

Yeah just checking the ratio rule, looks right.

Answer 41

yeah you will replace that row with a label of x4

Answer 42

looks good in fact the solution says you should end with x4 in the first row

Answer 43

So to turn 4/8 = 1, i do R1 = 8/4 x R1?

Answer 44

indeed or 2 in simplified form

Answer 45

And x3 being messed up now, doesn't matter?

Answer 46

nope perfectly fine, as the solution states when your finished, you will get x4 on the first line and x1 on the second line.

Answer 47

What a stupid reason to get stuck...

Answer 48

Can I quickly ask you about the others?

Answer 49

Sure I'll do what I can.

Answer 50

Better quality of the Q

Answer 51

(b) = Money (Euros in this case), and maximum level of Profit is 38 right? The final Z value?

Answer 52

Actually the equation seems to have converted the time

Answer 53

So I think there are some hidden powers of 10 there.

Answer 54

38 = 3880?

Answer 55

3800*

Answer 56

Lets see they said 12 of the fourth product and 2 of the first product, that would take let's see how much time,

Answer 57

I get 5 hours to make 12 and 2 in assembly time so perhaps 1000s

Answer 58

Ok

Answer 59

(c) = Optimal solution is unique, because? What would you say?

Answer 60

Not certain, and to be honest have to go for a bit.

Answer 61

Ok, thank you for your time.

Answer 62

Can anyone offer insight into part (c) (d) in this Q please?

Answer 63

i see how it is... bumping ahead of me