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Need help with working out the volume of a Tan(x) graph. My answer is always negative!
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y=0 and x=pi/3 about the x-axis
So what are you integrating?
\[\pi*\int\limits_{0}^{\pi/3}(tanx)^2dx\]
ok that looks good
I was unsure whether the formula was correct
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yeah since you are oscillating about the x-axis I would go with the integral of pi*y^2
after integrating tan^2x I get tanx-x. using that after substituting pi/3 I get a negative volume which I believe is impossible
not sure what im missing
hmm let me see, are you in radian mode on calc.
Dammit!!!
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I completely forgot about that
I was in degrees
Yeah that would do it, I think you were good.
thanks for the help
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