A polynomial function can be written as (x − 2)(x − 3)(x + 5). What are the x-intercepts of the graph of this function? (2, 0), (3, 0), (−5, 0) (−2, 0), (−3, 0), (5, 0) (2, 0), (3, 0), (5, 0) (−2, 0), (−3, 0), (−5, 0) Would this be A?
@welshfella
@.Sam. @MARC_D @ganeshie8
the x intercepts occur when f(x) = 0 so we can write (x - 2)(x - 3)(x + 5) = 0 what are the values of x which satisfy the above?
Note that if any of these factors are equal to 0 than the whole function equals zero.
So what value of x makes x - 2= 0?
-2
no for x - 2 to be = 0 x must be 2 (2-2=0)
now you need to find what value of x in (x - 3) and also (x + 5) make them = 0.
Yea sorry I am stupid XD
Ok, so it is A?
Thats what I thought before, just checking and kinda wanted an explanation. Thanks!
x + 3 = 0 so x = 3 x + 5 = 0 so x = -5
as -5 + 5 = 0
yes A is correct
Thank you!
yw
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