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What is the equation in standard form of a parallel line that passes through (0,-2)? The line parallel to (0,-2) is y=-4x+4
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Try using the same process I showed you, except using the fact that parallel lines have identical slopes.
Point-Slope form --> y = mx + b --> move mx to the left
\[y+2=-4(x-0)\]
-4 being the slope cause of the y=-4x+4
that's right, now to y = mx + b form
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\[y=-4x+2\]
Careful, you subtracted 2 from the left side, so you should subtract from the right as well.
But I did subtract... ? from \[y+2=-4(x-0)\] \[y=-4x+2\]
\[y + 2 = -4x\]\[y + 2 - 2 = -4x - 2\]
Oh right I forgot about the 0..
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\[y+2-2=-4x-2\] \[y=-4x-2\] \[4x+y=-2\]?
$$4x + y = -2$$ is correct :-)
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