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Chemistry 18 Online
OpenStudy (kittiwitti1):

1. Which of the following statements is/are incorrect? i. Undissolved sugar in contact with a saturated sugar solution in an open beaker cannot reach equilibrium ii. A liquid and its vapor enclosed in two one-liter containers connected by an open glass tube cannot reach equilibrium iii. A solution of a weak acid, hydronium ion, and the conjugate base of the weak acid cannot reach equilibrium a. i only b. ii only c. i and ii d. ii and iii e. i, ii, and iii

OpenStudy (kittiwitti1):

attached full document for questions

OpenStudy (kittiwitti1):

#1: i know (i) is true and (ii) is false but I don't know about (iii)

OpenStudy (cuanchi):

why they can not reach equilibrium?

OpenStudy (kittiwitti1):

(i) : true because saturated cannot accept any more due to solubility limit (ii) : liquid still has room for vapor on top (iii) : idk

OpenStudy (cuanchi):

The question is not very well written. It is not recommended to ask for the incorrect answers and also in the options use the negative form "can not reach". anyway, In a saturated solution you have an equilibrium. If you add more solute it will solubilize and some other will precipitate and the solution will reach equilibrium. The equilibrium it is dynamic always will be solute dissolving and other molecules precipitating. It is hard to understand what they means for can not reach equilibrium.

OpenStudy (kittiwitti1):

Saturated solution already reached the solubility limit, how is it possible to dissolve more?

OpenStudy (sweetburger):

It's not that the solid sugar isn't dissolving its that the rate at which the sugar dissolves into the saturated sugar solution is equal to the rate at which the sugar precipitates back out. So it would actually reach an equilibrium.

OpenStudy (kittiwitti1):

Oh. I hadn't thought of that woops

OpenStudy (kittiwitti1):

On that premise, would (ii) be ... \(incorrect\)?

OpenStudy (cuanchi):

I will said that all the options are incorrect since all the 3 system they are and they can reach equilibrium. What the open beaker comment is about? you have to consider that will be some water evaporation? or it is just a distraction comment?

OpenStudy (kittiwitti1):

I'm not sure how (iii) is wrong/right (idk). I don't understand what it's saying.

OpenStudy (sweetburger):

iii. When it comes to a weak acid dissolving into water we get this type of reaction \[HA +H_2O \leftarrow\rightarrow A^- + H_3O^+\] (Assuming that HA is a weak acid) This process will indeed reach an equilibrium in which the rate at which HA gives up an H+ will be equal to the rate at which A^- accepts an H+ from H3O+.

OpenStudy (kittiwitti1):

Ah, thanks

OpenStudy (kittiwitti1):

Okay and #2 (it's in the document as well)? 2. Which of the following conditions is not found in a system that is at equilibrium? a. Reactants and products are being converted into one another continually b. The forward rate of reaction is equal to the rate of the reverse reaction c. The concentration of reactants is equal to the concentration of the products d. The system is closed and isolated from its surroundings e. The reaction can be represented by an equation with a double arrow

OpenStudy (kittiwitti1):

(I apologize for bad formatting)

OpenStudy (sweetburger):

A system being at equilibrium only considers rates, and does not consider the concentrations of products and reactants.

OpenStudy (kittiwitti1):

I assumed C is wrong due to concentrations being negligible as long as they are proportional in ratio...

OpenStudy (kittiwitti1):

(C is wrong therefore the right answer, I mean)

OpenStudy (sweetburger):

Basically if you change the concentration of the reactants or products when a system is at equilibrium the system will move to reduce the stress of the added reactants or products, but the overall equilibrium constant would not be affected.

OpenStudy (sweetburger):

And yes C is the correct answer. gj

OpenStudy (kittiwitti1):

Thanks ☺

OpenStudy (sweetburger):

np :)

OpenStudy (kittiwitti1):

okay and ... 3 3. Which of the following statements is/are correct? i. An object hanging motionless on a spring is in a static equilibrium ii. In a dynamic equilibrium, the reversible changes occur continuously, even though there is no appearance of change iii. The amounts of substances present in a system at equilibrium are equal a. i only b. ii only c. iii only d. i and ii e. ii and iii (i) correct (ii) correct (iii) no because equality is negligible as long as they are in proportion ??

OpenStudy (kittiwitti1):

I had to apply physics to (i) lol

OpenStudy (sweetburger):

I don't know about i. as i don't remember specifically how springs work. But you are correct on ii. and iii.

OpenStudy (kittiwitti1):

Tension on spring ↓ (gravity) Spring pulls up ↑

OpenStudy (kittiwitti1):

so (iii) is incorrect and thus the answer is D ?

OpenStudy (sweetburger):

Yea, should be D.

OpenStudy (kittiwitti1):

Alright, thank you

OpenStudy (sweetburger):

np again. going to take a second to look into springs.

OpenStudy (kittiwitti1):

I hope you don't mind me putting more questions on here xD

OpenStudy (kittiwitti1):

(alright)

OpenStudy (sweetburger):

no, thats fine keep posting

OpenStudy (kittiwitti1):

ok and #5... Uh, I can't post that, but it's in the documents

OpenStudy (sweetburger):

time to find out if ms word has expired or not

OpenStudy (kittiwitti1):

LOL

OpenStudy (sweetburger):

Ok, i took a screenshot so others can see. https://gyazo.com/bf956f11adb86fd184ad4cff03ec7734 luckily still have ms word :P

OpenStudy (kittiwitti1):

Thanks ☺

OpenStudy (kittiwitti1):

I feel like all of them describe the diagrams

OpenStudy (mayankdevnani):

Option i is correct As all forces are balanced

OpenStudy (kittiwitti1):

eh?

OpenStudy (mayankdevnani):

Body is in motion less means body is in rest position It means all the forces are balanced to keep the body in rest position i.e in equilibrium

OpenStudy (kittiwitti1):

uhh is this #5?

OpenStudy (mayankdevnani):

#3

OpenStudy (kittiwitti1):

oh

OpenStudy (kittiwitti1):

okay thanks for confirm :D

OpenStudy (sweetburger):

Ok for question 5. Having too much potential energy would not cause an unsuccessful collision. Basically for a successful collision the atoms/molecules must collide with an energy greater than or equal to that activation energy of the reaction. So having too much PE would not be an issue.

OpenStudy (kittiwitti1):

So then that is the "incorrect" and thus CORRECT answer lol

OpenStudy (sweetburger):

Yes lol

OpenStudy (kittiwitti1):

Okay and ... 6 6. What kind of molecular collisions will not lead to the formation of product in a reaction? a. Only those without sufficient kinetic energy b. Only those with the wrong orientation, regardless of the kinetic energy c. Collisions between molecules that have more energy than the minimum required d. Those without sufficient kinetic energy and with the wrong orientation e. Those with effective collisions ANSWER:

OpenStudy (kittiwitti1):

(a) is one option of many so NO (b) same as A (c) sounds like the same thing as 5D (d) PRETTY SURE THIS IS THE ANSWER (e) uh what

OpenStudy (kittiwitti1):

I mean, (e) is effective which DOES lead to product. So it's not correct*

OpenStudy (sweetburger):

Molecules with wrong orientation, regardless of kinetic energy would cause for an unsuccessful collision and therefore no product formation. Then again answer choice d seems to be more inclusive. Badly written answer choices imo.

OpenStudy (kittiwitti1):

I agree xD btw if my reasoning is right just say Yes hahah (have class in half an hour !)

OpenStudy (kittiwitti1):

7. Which of the following statements is incorrect? i. The collision theory of chemical reactions states that what we see as a chemical reaction is the overall effect of a high number of individual collisions between reacting particles ii. A violent, bond–breaking collision is most apt to occur if the colliding molecules are moving at high speed iii. Most collisions do not result in a reaction a. iii only b. i and iii c. ii and iii d. All statements are correct e. All statements are incorrect I know (ii) is wrong, (iii) idk

OpenStudy (sweetburger):

Yea it looks pretty much right.

OpenStudy (kittiwitti1):

eh?

OpenStudy (sweetburger):

Yea most collisions dont result in a reaction for many reasons.

OpenStudy (sweetburger):

i. is correct. iii. is correct. still thinking about ii.

OpenStudy (kittiwitti1):

correct thus not the answer?

OpenStudy (kittiwitti1):

Right = the overall answer correct = if the Q asks for it lol

OpenStudy (sweetburger):

Yes correct thus not the answer

OpenStudy (sweetburger):

And ii. is also correct thus not the answer.

OpenStudy (sweetburger):

So all the statements are correct. none are incorrect

OpenStudy (kittiwitti1):

Alright

OpenStudy (sweetburger):

man they word these as confusing as possible

OpenStudy (kittiwitti1):

Brain exercise? xD

OpenStudy (sweetburger):

trying to make us pick the wrong answer choice. smh lol

OpenStudy (sweetburger):

yea true lol.

OpenStudy (kittiwitti1):

8. A molecular collision is sufficiently energetic to cause a reaction, yet no reaction occurs. Which of the following is the least likely explanation? a. The proton–proton interaction is too large b. The molecules have poor orientation c. One of the molecules is not moving too slowly. d. One or both the molecules does not have enough energy. e. All of the above could be an explanation. ANSWER: A. what. B. I think C. ... that would deviate from "sufficiently energetic" D. same as C E. hmm

OpenStudy (kittiwitti1):

E is wrong, I mean

OpenStudy (sweetburger):

"One of the molecules is not moving too slowly." what even is this wording. Does that mean its moving quick?

OpenStudy (kittiwitti1):

It's moving slow I think it's a typo

OpenStudy (sweetburger):

I think it could be all of the above. A. is describing that the (assumed) positive charged end of a compound has an interaction with the (assumed) positive charged end of the other compound in the collision. Therefore no product is formed.

OpenStudy (kittiwitti1):

b/c repulsion?

OpenStudy (kittiwitti1):

I mean if they have enough energy wouldn't they move at equal speeds

OpenStudy (sweetburger):

A. comes down to the like (positive) force between the positive ends of the compounds is too great. Just another way to word bad orientation.

OpenStudy (sweetburger):

Yea b/c repulsion.

OpenStudy (sweetburger):

Answer choice d. describes that the energy of the interaction between the molecules is not greater than or equal to the activation energy of the reaction.

OpenStudy (kittiwitti1):

the energy \(\ne\) activation energy. it needs a catalyst?

OpenStudy (sweetburger):

If you want to think that big of a picture then yes a catalyst would be required or small picture thinking is that the single instance collision just wasn't high enough energy

OpenStudy (kittiwitti1):

okay

OpenStudy (kittiwitti1):

got it

OpenStudy (kittiwitti1):

#9 asks for Ea or activation energy, on a diagram is that the part before the hill?

OpenStudy (sweetburger):

I'm assuming the answer would be e. (assuming that c has a typo). Otherwise the answer could be c.

OpenStudy (sweetburger):

The part before the hill is the potential energy of the reactants.

OpenStudy (kittiwitti1):

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