Question

f(x) = 3x + 9, g(x) = 5x^2

Find (f + g)(x).

Answer 1

@.Sam. @sweetburger @zepdrix

Answer 2

@kidrah69

Answer 3

@zepdrix do you know what to do?

Answer 4

\[\large\rm \color{royalblue}{f=3x+9}\qquad\qquad \color{orangered}{g=5x^2}\]Should be pretty straight forward,\[\large\rm \color{royalblue}{f}+\color{orangered}{g}=\color{royalblue}{3x+9}+\color{orangered}{5x^2}\]ya? :d

Answer 5

that's what i thought but this is my first time doing preC so i wnted to make sure I have a few more you down?

Answer 6

sure let's try another :D

Answer 7

f(x) = 2x + 6, g(x) = 4x2

Find (f + g)(x).

Answer 8

2x+6/4x^2 is it?

Answer 9

Why division? :o
(f+g)(x) basically just means add f and g.

Answer 10

that's a fraction

Answer 11

fraction = division

Answer 12

is that the correct answer ?

Answer 13

Question:

f(x) = 2x + 6, g(x) = 4x2

Find (f + g)(x).

Answer 14

I don't understand why you would guess the fraction...
Our first problem was almost exactly like this one :o
We didn't end up with a fraction.
We just added the pieces together.

Answer 15

yes it did? what these are my answer choices to the first problem:

-5x2 + 3x + 9

3x+9/5x^2

15x3 + 45x

5x2 + 3x + 9

Answer 16

B was the answer right?

Answer 17

it was D wasn't it

Answer 18

f=3x+9
g=5x^2

So f+g is going to be 3x+9+5x^2
which no, is not equivalent to B.

Answer 19

Yes D.
Just rearrange

3x+9+5x^2 = 5x^2+3x+9

Answer 20

I didn't put a fraction bar when I wrote the answer to the first one. Not sure where you got that from XD hehe

Answer 21

f(x) = 2x + 6, g(x) = 4x2

Find (f + g)(x). (1 points)

a. 8x3 + 24x

b. 4x2 + 2x + 6

c. -4x2 + 2x + 6

Answer 22

b?

Answer 23

Mmm yes, good.
These pieces added together.

Answer 24

f(x) = 4x + 6, g(x) = 2x2

Find (fg)(x).

a. 8x3 + 12x2
b. 2x2 + 4x + 6
c. 8x + 12
d. 8x2 + 12x

Answer 25

b again?