Question

Rate of change

Answer 1

@princeharryyy

Answer 2

a) i) (0-25)/(5-2.5) = -10,
ii) 0 to 1s => 16/1 = 16
iii) 1s tp 2s => (24 - 16)/(2-1) = 8

Answer 3

b) no, the rate of change in each case is different. The rate is given as

final value of height - initial value of height / final time - initial time

Which comes out to be different in each case. Moreover graph is not constant over the period of intervals.

Answer 4

Average rate over 5 seconds = > (0-0)/(5-1) = 0

Answer 5

are you sure?

Answer 6

of course! y ?

Answer 7

oh nvm, your correct :)

Answer 8

ok