Help with inverse of sine cosine and tangent functions please! I just need help understanding why we use -1 and how to use it https://static.k12.com/eli/bb/348/3_24097/1_45184_3_24100/9a450e8ab326bbc1d59f83f173e5ff2f7b83ffea/media/fe3fd7db89c23eebbecb6b2581211a410b4fcce6/mediaasset_659645_1.gif
Hello, This is History :) Here is a link to Math http://openstudy.com/study#/groups/Mathematics
* I'll answer this in detail later. Just remind me :p
so, we use the 6 trig functions (sin, cos, tan, csc, sec, and cot) to find the value of an angle For example, sin 45 degrees = sqrt(2)/2 We use sin with an angle to find the value. But what if we're given just the value? How would we find the angle? That's where the inverse of the trig functions come in to play. :)
so if they told you that for some angle x, the value of sin x is sqrt(2)/2 you would have sin x = sqrt(2)/2 and then you do inverse sin to get x alone x = sin^-1(sqrt(2))/2) sin^-1 is the same thing as arcsin
and you can use a calculator to find the inverse sign of a value :)
and also sin^-1(sin x) = x the inverse of sign of sin of x is going to be x :P
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