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√84y^7
@sleepyjess @confluxepic @TheSmartOne @ageta
@jim_thompson5910
The problem is this \[\Large \sqrt{84y^7}\] correct?
yea it is the problem
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we have to simplify it
what are some ways to factor 84? which factors are perfect squares?
4 and 21
good
with the y^7, we can break it up into y^6*y agreed?
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yep
So based on all that, we can say \[\Large \sqrt{84y^7}\] \[\Large \sqrt{4*21*y^6*y}\] \[\Large \sqrt{4y^6*21y}\] \[\Large \sqrt{4y^6}*\sqrt{21y}\]
what comes next?
2
square root of 4 is 2, yes how about the y^6 part?
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divide it by two
i think
yes 6/2 = 3 is the new exponent
So \[\Large \sqrt{4y^6}*\sqrt{21y}\] turns into \[\Large 2y^3*\sqrt{21y}\]
and that's as simplified as it gets
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oh i get it now
thank you
no problem
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