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@jim_thompson5910
how long is segment AD?
hint: DC = 4 AC = 20 AD+DC = AC
16?
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yes
The triangles are similar, so we can form this ratio \[\Large \frac{AD}{BD} = \frac{BD}{DC}\] \[\Large \frac{16}{h} = \frac{h}{4}\] Cross multiply then solve for h
h=8?
yep
So the answer would be 8?
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@jim_thompson5910 How do you do this one?
Using a similar idea, we can say \[\Large \frac{DC}{AC} = \frac{AC}{BC}\] \[\Large \frac{x}{15} = \frac{15}{20}\] Cross multiply then solve for x
x = 45/4
correct
Is this correct?
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It's not correct. Set up the following ratio (or something similar) \[\Large \frac{DC}{AD} = \frac{AD}{BD}\] \[\Large \frac{10}{x} = \frac{x}{3}\] Cross multiply then solve for x
Then it would be square root of 30
correct
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