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if m cotA = n, find the value of
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\[\frac{ msinA-ncosA }{ ncosA+msinA }\]
@TheSmartOne, a lil help here? ;-;
divide the numerator and denominator by sinA first
Oh, so it becomes \[\frac{ m-n * n/m }{ n * n/m + m}\]
Yea? ;-;
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no cheating :P
Whut do u mean? o.o
I did what u asked me to xD
What do we do from there?
|dw:1471421666777:dw| I know you're cheating because you did my step somewhere else and did another step and gave me that result :P We divide by sinA in both the numerator and denominator because that will give us some 1's and cos/sin which is cot so first divide both the numerator and denominator by sinA and simplify :)
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