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OpenStudy (kyle755):
Solve for x: 2 over 5 (x − 2) = 4x.
A. 2/9
B. 9
c. negative 2/9
D. negative 9/2
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OpenStudy (kyle755):
The second one
OpenStudy (confluxepic):
Is that
\(\frac{ 2 }{ 5(x-2)}\)
or
\(\frac{ 2 }{ 5 }(x-2)\)?
OpenStudy (confluxepic):
\(\Huge\frac{ 2 }{ 5 }(x-2)=4x\)
OpenStudy (confluxepic):
Just manipulate the equations. Simple. :)
OpenStudy (confluxepic):
First simplify them.
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OpenStudy (confluxepic):
Get rid of the fraction to make life easier. Do you know how to do that? @Kyle755
OpenStudy (kyle755):
yes 2/5 * 5/2
OpenStudy (confluxepic):
Good thinking. I like you.
Alright, what do you get after you multiply it by 5/2. (Remember to multiply both sides by the same thing.)
OpenStudy (kyle755):
1
OpenStudy (confluxepic):
\(\ (x-2)=4x \times (5/2)\)
Is that correct?
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OpenStudy (kyle755):
no
OpenStudy (confluxepic):
Why not? I multiplied both sides of the equation by 5/2.
OpenStudy (kyle755):
it would be yes
OpenStudy (confluxepic):
\(\ x-2=4x \times (5/2)\)
What is 4x times 5/2?
OpenStudy (kyle755):
6
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OpenStudy (confluxepic):
\(\Huge\ I~am~going~to~solve~only~the\\\Huge\ right~side~of~the~equation.\)
\(\Huge\ 4x \times \frac{5}{2}=\)
\(\Huge\ \frac{4x\times 5}{2}=\)
\(\Huge\ \frac{20x}{2}=\)
\(\Huge\ 10x\)
\(\Huge\ x-2=10x\)
OpenStudy (confluxepic):
Can you do the rest or do you need more of my help?
OpenStudy (kyle755):
ok and thank you and I can do the rest
OpenStudy (confluxepic):
You're welcome. :)
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