Question

I am confused as to what I am doing wrong. Please Help. :(

Answer 1

okay whats your approach to the problem?

Answer 2

Took the derivative and solved for x to get
\[cosx=\frac{ 1 }{ 2 }\]

Therefore,
\[x= \frac{ \pi }{ 3 } and \frac{ 5\pi }{ 3 }\]

Answer 3

your derivative is incorrect

Answer 4

Oh \[cosx=\frac{ -1 }{ 2 }\] ?

Answer 5

the derivative seems correct to me hmm

well your general solution should be like \(2n\pi \pm \frac{\pi}{3}\)

Answer 6

f(x) = x - 2 sin x
f'(x) = 1 - 2 cos x
when f'(x)= 0
cos x = 1/2

sorry you were correct the first time

Answer 7

Your answer looks correct.
Maybe they want it placed in the box like this,\[\large\rm \boxed{\frac{\pi}{3}\pm 2n \pi,\qquad \frac{5\pi}{3}\pm 2n \pi}\]maybe?

Answer 8

yeah he didn't put that \(\color{red}{\pm}\)

Answer 9

without the `x=` portion

Answer 10

Oh n is an `integer`, not a natural number,
so simply + is fine.

Integer includes all the negatives.

Answer 11

Oh haha. Yea i just had to take out the "x=" portion. You were right. Thank you!

Answer 12

ahh you silly billy -_-

Answer 13

Hehe :P