Solve for x: −2x + 5 < 7 (1 point)
x > −1
x < −1
x > −6
x < −6
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OpenStudy (mathwizzard3):
What do you think you do first?
OpenStudy (impracticaljoker):
I was thinking that < would act as a = sign so subtract 5 on both sides?
OpenStudy (mathwizzard3):
Yep! The only difference is that if you divided or multiply by a negative you flip it
OpenStudy (impracticaljoker):
so -2x > 2
OpenStudy (mathwizzard3):
Yeah! Now you would?
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OpenStudy (impracticaljoker):
divide -2 on both sides?
OpenStudy (mathwizzard3):
Yup and because you are dividing by a negative you would flip it
OpenStudy (impracticaljoker):
I don't have my caculator.
OpenStudy (mathwizzard3):
So
x > -1
OpenStudy (mathwizzard3):
Hope that helped ^-^
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OpenStudy (impracticaljoker):
Thanks! Can you help me with a couple more?
OpenStudy (mathwizzard3):
Sure!
OpenStudy (impracticaljoker):
Should I open a new thread or post it here?
OpenStudy (mathwizzard3):
I think your suppose to open a new one but here is fine c:
OpenStudy (impracticaljoker):
Ok
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OpenStudy (impracticaljoker):
This one is a little more complex
Solve for x: 3 − (2x − 5) < −4(x + 2) (1 point)
x < −8
x > −8
x < −3
x > −3
OpenStudy (impracticaljoker):
I don't know where to start
OpenStudy (impracticaljoker):
Im guessing you're baffled as well.
OpenStudy (mathwizzard3):
Oh wait no I was getting distracted
OpenStudy (mathwizzard3):
First you would distribute the negative sign on the left side
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OpenStudy (impracticaljoker):
how? .-.
OpenStudy (mathwizzard3):
Okay it' does sound a little confusing let me draw a picture
OpenStudy (impracticaljoker):
ok
OpenStudy (mathwizzard3):
|dw:1472234634590:dw|
So the 3 just stays and you multiply everything in the parenthesis by that negative sign but the trick to remember is that the negative sign secretly has a one so it is a -1