Two quadratic functions are shown. Function 1: f(x) = 3x2 + 6x + 7 Function 2: x g(x) −2 13 −1 7 0 3 1 7 Which function has the least minimum value and what are its coordinates?
@JoCelM
can you help
Possibly, you can find the minimum value of a quadratic function by using the formula -b/2a so -6/3*2 so -6/6 so the minimum value for the first one is -1. then, try to plot the values of the second function the lowest y value or g(x) value in this equation is what?
wait what
Yes that's what i was going to say. Use the function -b/2a in the function ax^2+bx+c
It helps you find the vertex of the problem or other words the "minimal value"
and ax²+bx+c is the standard form of a quadratic that's where I got my a and b from, the equation is 3x²+6x+7 so 3 is a and 6 is b and 7 is c.
So 3x^2+6x+7 is a=3 b=6 c=7 because the original function
so it would be Function 2 has the least minimum value and its coordinates are (−1, 7).
No. You want the lowest possible y value, out of those 2 equations which has the lowest y value?
ok functioon 2 u just look for the lowest y value, this case 3
Function 2 has the least minimum value and its coordinates are (0, 3).
so the coordinates are 0,3 and function 1 is....
y is g(x) in function 2 and the lowest y value is 3. the first equation we calculated with our equation to have the lowest y value of -1
so I'm right?
Now you use that -1 and plug that into the equation u are given to get the y value
No, the first equation has the lowest y value.
omg im lost
Wait I forgot to plug it in so you plug it back in to get the lowest y value lol oops
ok so Function 1 has the least minimum value and its coordinates are (−1, 4). what I'm thinking
wait which one
was it Function 2 has the least minimum value and its coordinates are (0, 3)
was it?
hurry my assignemnt ends in 3 mins
so plug in -1 for x in the first equation.... that's your x value....lets find your y value....if f(x) which is y so....if y=3x²+6x+7 and x is -1 -1² is 1... 3*1=3+(6*-1)+7 ...(6*-1) is -6 so....3-6+7 is y....so y is 1 in the first equation....so x,y is -1,1 so which out of the two graphs has the lowest y value? it's the first one and it's coordinates are -1,1
In conclusion it's the first graph and -1,1 are the coordinates.
Which function has the least minimum value and what are its coordinates? Function 1 has the least minimum value and its coordinates are (−1, 4). Function 1 has the least minimum value and its coordinates are (0, 7). Function 2 has the least minimum value and its coordinates are (−1, 7). Function 2 has the least minimum value and its coordinates are (0, 3).
its not one of the answers
I must've went wrong somewhere....
NO its -1, 10 I think you calculated wrong
Sorry I wasnt being mean. I needed your attention'
3x^2 is (-3)^2 which is 9-6+7
function 2 with 0,3 hurry bud!
so i do 9-6+7
i got all them right with you guy
THANKS SO MUCH
I see where I went wrong haha.
No its not 10 ahhh. Im lost
ITS Function 2 has the least minimum value and its coordinates are (0, 3).
i got it right
hey he got it right, we're good. gimme a sec and I'll see what function1's coordinates were lol
Im confused if the vertex of func 1 is -1 how do you get the y value as 7?
or 4
y value of that one is 10 I believe....
YES!!! ok im not going crazy but her choices didnt have -1, 10
Ok, im gonna blame the answer choices and believe I did it right hopefully :)
oh oops I said he and she's a she.
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