the sum of a number and its reciprocal is 61/30. find the number
Start by choosing a variable. Do you like x?
yea I wrote x+1/x = 61/30 but i'm not too sure that's the right way
that is the correct way. you can multiply both sides (all terms!) by x as the next step.
Your equation is correct. Do you need help solving it?
If i multiply all the terms by x, i would get x^2 but what about the 1/x ?
The x's will cancel there. \(\dfrac{1}{x} \times x = \dfrac{1}{x} \times \dfrac{x}{1} = \dfrac{x}{x} = 1\)
Okay I thought it would be that way I was just very confused. Thanks!
don't forget to multiply the 61/30 by x also
Okay
what do you have so far?
\[x ^{2} -\frac{ 61 }{ 30 }x +1 \]
=0
I will be using quadratic formula to solve for x
yes.
This question is on my textbook and it tells me I cannot use a calculator, is there any easy way to solve without having to multiply so many fractions?
\(x \times x + \dfrac{1}{x} \times x = \dfrac{61}{30} \times x\) \(x^2 + 1 = \dfrac{61}{30} x\) \(x^2 - \dfrac{61}{30} x + 1 = 0\) Now continue with: \(x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
interesting. it almost sounds like there is a short-cut.
It is easy with a calculator but it is very weird without one
we could multiply by 30 (both sides, all terms) to get \[ 30 x^2 -61x +30=0 \] but that still looks hard to do without a calculator.
oh, we do get (relatively) nice numbers
I got it haha
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