Question

S.O.S

Answer 1

!!

Answer 2

Uhmmm. What grade is this?

Answer 3

Tyren just help >.>

@MissSmartiez so what choice you pick for number 1? or you need that explained?

Answer 4

Back, and yes, I do need assistance on number one.

Answer 5

and two))

Answer 6

Well \[\frac{ 36 }{ 6 }\] is what?

Answer 7

6

Answer 8

Right 6, but now you see that it's -36 so 6 would be negative 6
you get this?

Answer 9

Oh, I see, is that how you find out what a negative square root number is?

Answer 10

That should be

Answer 11

Alright, how about number two? Is it D?

Answer 12

OKay it's kinda blury for me

does it say \[x^3?\]

Answer 13

Correct.

Answer 14

It does.

Answer 15

D. not is right

Answer 16

No the answer should be C since just factor by using difference of cubes and set each factor that would equal to 0.

Answer 17

bc. -5^3 = -125 and there is +125

Answer 18

Oh. My lesson says:

Square Root:

If a^2 = b, then a = ±(square root)b

So it only goes with ^2?

Answer 19

but you wrote there radical index 3

Answer 20

I was confused on C and D, so I figured it was D because of the tip.

So, it only goes for (x^2) <---

Answer 21

I know. Thats why I said, it only goes for ^2 and not ^(anything but two)

Answer 22

?

Answer 23

but there on this exercise posted wrote x^3 = 125/27

Answer 24

I know.

My lesson said a^2 = +/-, and I figured if any a^(any exponent number) would equal +/-, so I was confused and asked if thats what it was referring to. I made a mistake. It only works for ^2.

Answer 25

yes this is right just for a^2 bc for example sqrt9 = +/- 3 bc. 3*3=9 and
-3 *(-3) = +9 too

ok. ?

Answer 26

Alright, thank you.