Question

Need help with a quadratic equation :) Will medal

Answer 1

Please type in the question right away; then, if you wish to offer a medal, do that second.
Your equation? What are you supposed to do with it?

Answer 2

solve by completing the square

x^2 - 4x + 57 = -5

Answer 3

Much better. Have you used the "completing the square" approach before?

What is HALF of the coefficient of x in the given equation?

Answer 4

I have tried to just post my question first and no one ever looks at it. The only way someone will help me is if i say ill give them a medal.

I went over this in class today and from what i remember you first have to make sure the leading coefficient is 1 which it is.
then you have to move the whole number to the right side of the equation which i did to get x^2 - 4x = -62

Answer 5

then youre supposed to take the middle term which is -4x and divide by 2 which is -2 and then square it to get 4.

then you add 4 to both sides of the equation to get

x^2 - 4x + 4 = -58

Answer 6

then you factor it out and get
(x - 4)^2 = -58
and take the square root of both sides
x - 4 = sqrt(-58)

now im stuck

Answer 7

x^2 - 4x + 57 = -5

What is the coefficient of x in the above equation? I asked you this before. It's essential you know what a "coefficient" is and where to find the "coefficient" of a specific power of x. Here I've asked you to find the coeff. of the first power of x.

Answer 8

-4

Answer 9

Great. Correct. Now, please take half of this coefficient (take half of -4) and square the result. It's this square that you add to both sides of your equation. Show your work, pls.