I'm really stuck, please help. Line AR = 12, line BD = 10. Using the Pythagorean Theorem, show that Line AB is approximately equal to line AD. I can take a pic of the problem but I don't know how to attach. The prob has X and y axis. A is at the top of the y axis. B is to the far left of the X axis. D is at the far right of the X axis and r is at point 0,0
use the "snipping tool" It takes a screenshot on the computer
Use the attach file tools
I'm on an iPad. Can you advise or should I move to a laptop?
Yikes, I don't have an ipad so I wouldn't know. Windows computer has a snipping tool if you just search it.
Is the problem a triangle?
|dw:1472525444412:dw| this maybe?
No, start by drawing a vertical line and a horizontal line, much like a plus sign. At the top of the vertical line, write A. At the bottom of the vertical line, write C. To the far left of the horizontal line, write B. To the far right of the horizontal line, write D. At the intersection of the two lines, write R. One more thing, there is a small mark mid way between the R and B and the same small mark between the R and D. The Mark just looks like a tic on graph paper. Does that help?
So it forms a graph, kinda?
Strongly advise learning and practicing ways in which you can share images from your iPad. If the Pythagorean Theorem is applilcable here, that means the triangle is a right triangle. Note that the longest side of this triangle is the hypotenuse. A triangle has only 3 vertices, so it's confusing if you list more than 3: A, R, B, D, r. If a diagram came with this problem, it's just about essential that you share it.
Agreed @mathmale
Yes, like two lines on graph paper. No triangle drawn. Just points labeled asA B C D and R
|dw:1472525676233:dw| so looks kind of like that?
Looks EXACTLY LIKE THAT just add the D on the right side
It is there. lol
Sorry, can't see it. But you nailed it! So, the prob says line AR = 12, line BD = 10, using the Pythagorean Theorem, show that AB ~= AD
Can you help, please?
|dw:1472525883257:dw| So you need to find the length to R to D first.
Line AC intersects line BD in the middle right? So RD would be half of BD...
Or 5
Yes. :P
There's got to be more to it, right?
|dw:1472526181489:dw|
Excuse all the hot air coming from me, Blowery, but you've really got to post a screen capture or actual photo of this problem and all of the instructions. Your life will become easier once you've learned to do this.
@mathmale lol, they didn't know how to, and the rest of us don't know how to from an ipad so he had to explain it
@BLowery figure out what x is from the equation I gave you
I agree and will work hard to figure out how to share pic tomorrow but it's pretty late tonight and hellppp nailed the drawing from my description
I will solve for x
I'm glad helpppp has more patience than I under the present circumstances.
Lol. XD It would be more irritating if there were a triangle plotted on the graph. XD
You really helped me a lot and I am very thankful!
You got it from there? You would just need to find y based on what x was. :P And then youd have your answer
I'm trying, but you have AD labeled as 12 and the prob gives AR = 12. I think solving for the unknown is the same process though, right?
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