Question

5x^2+20=20x

Answer 1

\[5x ^{2}+20=20x\]

Answer 2

just divide every term bu 5... then it will be easy to factor

Answer 3

like a first step subtract from both sides 20x and after this factoriz out 5 from both terms

Answer 4

5x^2 -20x +20 = 0
5(x^2 -4x +4) = 0

Answer 5

thats not the answer

Answer 6

Subtract 20x from both sides
\[5x^2+20−20x=20x−20x\]
\[5x^2−20x+20=0\]
Than factor left side of equation
\[5(x−2)(x−2)=0 \]

Answer 7

at last se et factors equal to 0, which would look like this
\[x−2=0 \] or \[x−2=0\] \(\ x=2 \) should be your answer

Answer 8

thamk you so much kinda late but thats the answer i needed lol

Answer 9

Sorry, lol if you need any other help just tag meh..

Answer 10

alright thanks