What is the x-intercept of f(x)=-(x+8)^2+12?

Question

jim_thompson5910 · Answer

Replace f(x) with 0. Then solve for x.
$$\Large f(x)=-(x+8)^2+12$$
$$\Large 0=-(x+8)^2+12$$
$$\Large 0-12=-(x+8)^2+12-12$$
$$\Large -12=-(x+8)^2$$
$$\Large -(x+8)^2=-12$$
$$\Large (x+8)^2=12$$
Do you see what to do next?

triciaal · Answer

can you respond to the question?

epistemophile · Answer

Treat your f(x) as the value of y for which x is placed. You know that the x intercept occurs when y=0, so simply make f(x) valued at 0, and solve the other side of the equation

mathmale · Answer

You need to solve the equation (x+8)^2=12.  There will be two results.  Please check to ensure that one or both of these results is actually a solution of the original equation.