4 - 3 ln x = -8 I'm really not getting this math thing , y'all
\[\large\rm 4-3 \color{REd}{lnx} = -8\] can you solve for `lnx` ??:=))
is the answer 4?
thats wha† i got
how did you get 4?
ahh btw we have to solve for x therfore we have to take `e` both sides in order to cancel out ln but first get rid of all the numbers that are on the left side \[e^{\ln x} = x\]
jst solving for `lnx` wouldn't give u the final answer.
im so confused :(
You're on the right track so far, just need to finish it.. I'm assuming you ended up with \(\large lnx =4\) ?
Yessss
Now use what Nnesha suggested earlier with "e" (:
but i dont get where the e comes in? or what im doing with it
okay thats fine \[\large\rm 4-3lnx =-8\] first subtract 4 both sides and then divide by -3 |dw:1472705945254:dw| \[\frac{ - 3\ln x }{ -3}=\frac{-12}{-3} \rightarrow lnx=4\] now rewrite both sides as an exponnet of e
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