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Mathematics 13 Online
OpenStudy (kg1975):

Kg1975 Help Room!

OpenStudy (kg1975):

@Kimberly_PR

OpenStudy (kimberly_pr):

Haha, thank you :)

OpenStudy (kg1975):

yw lol

OpenStudy (kg1975):

i can get to this room easier when i go to help others i can see when u type ill come back XD

OpenStudy (kimberly_pr):

Great! And I already have my next question :) lol

OpenStudy (kg1975):

ok kelly tagged me in brb

OpenStudy (kimberly_pr):

Factor by grouping: 2u^3 + 3u^2 - 10u - 15

OpenStudy (kg1975):

ok see if u can maybe figure it out like before if not ill help ive had this problem in another room XD

OpenStudy (kimberly_pr):

UGGH omg I'm sooo bad at factoring :/

OpenStudy (kg1975):

ok ill explain it XD

OpenStudy (kimberly_pr):

Yes please, lol

OpenStudy (kg1975):

2u3+3u2-10u-15 Final result : (u2 - 5) • (2u + 3) Step by step solution : Equation at the end of step 1 : (((2 • (u3)) + 3u2) - 10u) - 15 Step 2 : Equation at the end of step 2 : ((2u3 + 3u2) - 10u) - 15 Step 3 : Checking for a perfect cube : 3.1 2u3+3u2-10u-15 is not a perfect cube Trying to factor by pulling out : 3.2 Factoring: 2u3+3u2-10u-15 Thoughtfully split the expression at hand into groups, each group having two terms : Group 1: -10u-15 Group 2: 2u3+3u2 Pull out from each group separately : Group 1: (2u+3) • (-5) Group 2: (2u+3) • (u2) ------------------- Add up the two groups : (2u+3) • (u2-5)

OpenStudy (vanesaretana):

..

OpenStudy (kg1975):

@helpppp

OpenStudy (helpppp):

I was requested?

OpenStudy (kimberly_pr):

And is that u^2? @kg1975

OpenStudy (kg1975):

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B) Proof : (A+B) • (A-B) = A2 - AB + BA - B2 = A2 - AB + AB - B2 = A2 - B2 Note : AB = BA is the commutative property of multiplication. Note : - AB + AB equals zero and is therefore eliminated from the expression. Check : 5 is not a square !! Ruling : Binomial can not be factored as the difference of two perfect squares. Final result : (u2 - 5) • (2u + 3) Yes it is kimberly

OpenStudy (kimberly_pr):

Awesome, thank you :)

OpenStudy (kg1975):

yw Helpppp tutored me a lil bit in math and i wasnt totally for sure but im pretty sure i got this right i just wanted her to double check and she said i was corect

OpenStudy (kg1975):

idk yet DX

OpenStudy (helpppp):

Yeah, ya gots it. *highfives you*

OpenStudy (kg1975):

haha

OpenStudy (kimberly_pr):

Factor 10y^2 -23y +12

OpenStudy (helpppp):

Is that one by grouping too?

OpenStudy (kimberly_pr):

It doesn't say, it just says factor

OpenStudy (kg1975):

((2•5y2) - 43y) + 12 Step 2 : Trying to factor by splitting the middle term 2.1 Factoring 10y2-43y+12 The first term is, 10y2 its coefficient is 10 . The middle term is, -43y its coefficient is -43 . The last term, "the constant", is +12 Step-1 : Multiply the coefficient of the first term by the constant 10 • 12 = 120 Step-2 : Find two factors of 120 whose sum equals the coefficient of the middle term, which is -43 . -120 + -1 = -121 -60 + -2 = -62 -40 + -3 = -43 That's it Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -40 and -3 10y2 - 40y - 3y - 12 Step-4 : Add up the first 2 terms, pulling out like factors : 10y • (y-4) Add up the last 2 terms, pulling out common factors : 3 • (y-4) Step-5 : Add up the four terms of step 4 : (10y-3) • (y-4) Which is the desired factorization Final result : (y - 4) • (10y - 3)

OpenStudy (kimberly_pr):

Omg thank you so much

OpenStudy (kg1975):

yw here is a medal for u for good questions XD some of ur questions are very hard but i try XD thats why i asked helpppp before XD

OpenStudy (kimberly_pr):

Thanks :) that was nice

OpenStudy (kimberly_pr):

Abdul is going to rent a truck for one day. There are two companies he can choose from, and they have the following prices. Company A charges $109 and allows unlimited mileage. Company B has an initial fee of $55 and charges an additional $0.90 for every mile driven. For what mileages will Company A charge less than Company B? Use m for the number of miles driven, and solve your inequality for m

OpenStudy (kg1975):

dang word problems! im horrible let me get helpppp for this 1

OpenStudy (kg1975):

@KingNoob @helpppp

OpenStudy (kg1975):

@quickstudent

OpenStudy (kg1975):

@mathmate

OpenStudy (kg1975):

@kittiwitti1

OpenStudy (kg1975):

ok while i wait for them imma try and figure this out XD

OpenStudy (kg1975):

a=127 b=55+.9m Solve: a >= b 127 >= 55+.9m 72 >= 0.9m m <= 72/0.9 --- m <= 80 miles (a >= b when # of miles <= 80)

OpenStudy (kg1975):

A(x) = 127x dollars B(x) = 55 + 0.9x dollars

OpenStudy (kg1975):

@kingethan8500 @kittiwitti1 @mathmate @quickstudent

OpenStudy (kittiwitti1):

\(\large\text{Sorry, trying to finish my Calculus homework.}\)

OpenStudy (kittiwitti1):

And... you tagged me twice. :v

OpenStudy (kg1975):

oh its ok i just wanted to know if im correct im trying to help my friend kimberly but im horrible at word problems .this is her question Abdul is going to rent a truck for one day. There are two companies he can choose from, and they have the following prices. Company A charges $109 and allows unlimited mileage. Company B has an initial fee of $55 and charges an additional $0.90 for every mile driven. For what mileages will Company A charge less than Company B? Use m for the number of miles driven, and solve your inequality for m my answer is...

OpenStudy (kittiwitti1):

Sorry, I can't. But good luck on finishing ☺

OpenStudy (kittiwitti1):

And you're a great friend for helping! ^^

OpenStudy (kg1975):

ok

OpenStudy (kg1975):

A(x) = 127x dollars B(x) = 55 + 0.9x dollar a=127 b=55+.9m Solve: a >= b 127 >= 55+.9m 72 >= 0.9m m <= 72/0.9 --- m <= 80 miles (a >= b when # of miles <= 80)

OpenStudy (kg1975):

got it kimberly?

OpenStudy (kimberly_pr):

I got it :) and no more word problems I promise, lol

OpenStudy (kg1975):

its alright ill figure it out if u have word problems! XD

OpenStudy (helpppp):

Sorry, I'm trying to cook, do my pre calc work and write an essay....

OpenStudy (kimberly_pr):

Just one more factoring problem since I know you are GREAT at those :)

OpenStudy (kg1975):

its ok

OpenStudy (kg1975):

ok let have at it! XD

OpenStudy (kimberly_pr):

Factor 3y^2 + 14y -5

OpenStudy (kg1975):

factor 3y^2-14y-24 Use the AC Method: AC = 3*-24 = -72 B = -14 --------------- Think of two numbers whose sum is -72 and whose product is -14 The numbers are -18 and +4 ------------------------------ Rewrite the original problem putting -18y+4y in place of -14y: = 3y^2-18y+4y-24 Factor the 1st two and the last two terms separately: = 3y(y-6)+4(y-6) with that try and figure out the answer i know it so if u dont then ill tell you ok

OpenStudy (kimberly_pr):

Ok so it would be (3y^2-18y)(4y-24) right?

OpenStudy (kg1975):

ehh thats an equation to find the answer... but anyways the answer is (y-6)(3y+4) i was trying to find an easy way to explain that but i couldnt XD

OpenStudy (kg1975):

Factor the 1st two and the last two terms separately: = 3y(y-6)+4(y-6) Factor again: = (y-6)(3y+4)

OpenStudy (kg1975):

so the answer is (y-6)(3y+4)

OpenStudy (kg1975):

just tag me if u need me but im closing this room and making a new 1 its to full XD

OpenStudy (kg1975):

ok?

OpenStudy (kimberly_pr):

Ok :) well I think I'm actually done for the day. Thanks for everything :) @kg1975

OpenStudy (kg1975):

ok well if u need anything ask and ill tag u into another private help room

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