Question

Can someone look through this pls.

Answer 1

I got \[\frac{ \pi }{ 24 } + \sin \frac{ \pi }{ 24 }\]

Answer 2

I get Pi/6 -pi/8 + sqrt3/8 -1/4

Answer 3

\(\pi/24+sin(\pi/24)\)
cannot be right because the second term has to be negative.
Yes,@alekos, I get the same answer.
\(\Large \frac{1}{2}(\frac{\pi}{3}+\frac{1}{2}(\sin(\frac{2\pi}{3}))-\frac{1}{2}(\frac{\pi}{4}+\frac{1}{2}(\sin(\frac{2\pi}{4}))\)
=\(\Large \frac{1}{2}(\frac{\pi}{3}+\frac{1}{2}(\frac{\sqrt{3}}{2}))-\frac{1}{2}(\frac{\pi}{4}+\frac{1}{2}(1))\)
=\(\Large\frac{4\pi+3\sqrt{3}-3\pi-6}{24}\)
=\(\Large\frac{\pi}{24}+\frac{\sqrt{3}-2}{8}\)

Answer 4

Oh I see, I distributed the 1/2 before solving for sin and messed up. Thank You.

Answer 5

You're welcome! :)