Question

can please correct this for me i will fan and medal

Answer 1

its okay thanks anyways @kg1975

Answer 2

Yw. try asking @helpppp @mathmale and @quickstudent

Answer 3

@agent0smith @FaiqRaees @mathisfun13
Try these people, I'm sorry my mind is too caught up in chemistry right now.

Answer 4

its okay thanks tho @quickstudent

Answer 5

Okay, so you want to do A first?

Answer 6

yes

Answer 7

helpppp is correct: somehow you lost the variable 't' in the 2nd expression.

Answer 8

it makes more sense now lol thanks

Answer 9

Also, it should come out to be a -16t^2.... so, change it a little more to get that part right...

Answer 10

lol

Answer 11

Please don't just tell them the answer, we need them to figure it out for themselves. Thank you

Answer 12

But yes, that was it... Now we can move to part B.

Answer 13

can you explain how to get that because im abit confused now -.-

Answer 14

Okay. Haha I can. You see your initial equation has a negative 16t^2 right? Well we need to get our outcome to be that as well.

Answer 15

oh lol it makes more sense now

Answer 16

-16t^2+60t or -4t(4t-15)?

Answer 17

Yes! :D

Answer 18

im surprised i even got it right

Answer 19

You could have also written it as 4t(-4t+15) Your outcome would have been the same. :P But good job. Shall we go onto B?

Answer 20

yes :p

Answer 21

Regarding Part B: Check: what is the square of 2? How did you get 16?

You begin with h(t) = -16t^2 + 60t.

In Part B, just let t=2 sec.

What is h(2)=-16(2)^2 + 60(2)?

Answer 22

You can use either equation that you have now. -16t^2+60t or you can use the one you have just created. fill in for t on which either one you use

Answer 23

@mathmale they had used the equation they came up for on part A, there were a few mistakes in their equation though, so it affected their outcome for part B

Answer 24

That's true. Using the original equation requires fewer calculations and thus leaves less room for error.

Answer 25

so do i solve the equation h(2)=-16(2)^2 + 60(2)?

Answer 26

Alexis: In part A, you seem to have lost the - sign. Fix that.

Answer 27

Mathmale, we have already done that. :)

Answer 28

Not solve, Alexis, but EVALUATE. Find the value of f(2).

Answer 29

You MUST multiply 2(2) before you multiply by 16, due to order of operations rules.

Answer 30

Okay, to solve h=-16(2)^2+60(2)
1. do your exponents. 2^2

2. multiply out -16(the outcome of 2^2)+60(2)

Answer 31

1. 2^2 would be 4

Answer 32

correct, so now you just do part 2. :D

Answer 33

Hey, you two: Check this out: that multiplier 16 applies ONLY to the first term of the equation in Part A.

Answer 34

-16^4+60(2)?

Answer 35

Mathmale, I told them the 2nd equation that they could use. However, the outcomes are still the same

Answer 36

yes. label it: f(2)=-16(4) + 60(2) = ?

Answer 37

It wouldn't be -16^4 but, it would be -16(4).

Answer 38

oh okay got it

Answer 39

Lemme know what you get

Answer 40

56?

Answer 41

correct! Now to do c

Answer 42

Use the same steps that we used in part B but fill in 3.75 for t

Answer 43

so it would be -16(4)+60(3.75)?

Answer 44

\[-16(3.75)^2+60(3.75)\] would be it. Haha, I should've stated you replace t with 3.75 in your initial equation

Answer 45

so i have to solve -16(3.75)^2+60(3.75)? @helpppp

Answer 46

Yes. :D Now, do your exponent first, 3.75^2

Answer 47

some how i got 0 as my answer -.- am i right?

Answer 48

That is what I got as well when I used hat equation, however that would seem odd considering that at2 seconds it was at 56. So let's try using our othe equation and fillin in for t.

Answer 49

4(3.75)(-4(3.75)^2+60(3.75)) do i put that in the calculator?

Answer 50

Yes. See what you get. and based on the result we will decide if the answer for b was also wrong... It's odd that they would give us a different outcome like that. but the rocket should be getting higher, not lower

Answer 51

true

Answer 52

I'm sorry about that. lol I mean mathmale also said to use the initial equation, but it doesn't work for c like it should

Answer 53

i got 2531.25

Answer 54

i think that makes less sense @helpppp

Answer 55

Hmm, lemme ask someone for some help real quick...

Answer 56

okay

Answer 57

@AloneS Can you check to see what went wrong?

Answer 58

@Will.H

Answer 59

Why would u assume it's wrong.. Those equations are for the falling objects at the vertex they get a velocity of. 0 so... Also u could always graph it and see if u correct or not

Answer 60

You are given a formula for height: h(t)=-16t^2 + 60t.

After 2 sec, the height is h(2)=-16(2)^2 + 60(2) feet. The first term comes out to -64 feet. What is the value of the 2nd term? What is the overall value of h(2)?

After 3.75 sec, the ht. is h(3.75)=-16(3.75)^2 + 60(3.75). Evaluate this. Show ALL work, please.

Answer 61

okay thank you @mathmale and @Will.H

Answer 62

Happy to be of help. These problems become easier as you practice them.