function question: Given h(x)=5, find: a. h(2) b. h(x+3) c. h(-x)
Do you know where to start with this?
No
so for a function, like f(x)=x, if it's f(1)=1, you just replace the x with your number. In this case, you may be overthinking it.
How am I overthinking it?
how can you solve h(2) if there is nothing to plug in? I'm just really confused
Right, so what does the function tell you? No matter what you plug in for x, the answer will be 5.
So the answer is h(2)=5?
Yep!
Okay thank you, so the second one is just h(2+3)=5?
Also I'm a bit confused why h(2) would equal five, like logically speaking. I understand the concept but still.
If you graph the function, it would be a horizontal line at y=5, so no matter what x equals, the answer will always be five.
That makes sense, thank you!
would the second one be h(2+3)=5 and the third one h(-5)=5?
Examples to clarify: if h(x)=5+x, then h(1)= 5 +1 and h(1)=6 if h(x)=5x, then h(1)= 5(1) and h(1)=5 if h(x)=5, then h(1)= 5, and h(1)=5
Thank you this is easier to understand.
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