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Mathematics 15 Online
OpenStudy (breanna.rae):

g

OpenStudy (loser66):

where are you stuck?

OpenStudy (loser66):

the first one is 2.5, not -2.5. double check, please

OpenStudy (loser66):

If you can get the first one, then do the same with the second one. I type the first one for you like this \(\dfrac{3\color{red}{x}+2\color{blue}{y}}{-\color{orange}{z}}=\dfrac{3\color{red}{(-1)}+2*\color{blue}{4}}{-\color{orange}{(-1)}}=\dfrac{-3+8}{2}=-2.5\)

OpenStudy (loser66):

just replace the values of x, y, and z into the expression. Go ahead, you can do it.

OpenStudy (loser66):

Just do the same. show your try, please

OpenStudy (leenathan):

ok so let me explain

OpenStudy (leenathan):

absolute value is when a number is put in || like the absolute value of 1= 1 and the the absolute value of |-1| still equals 1

OpenStudy (leenathan):

got it?

OpenStudy (leenathan):

yep like |1| ad |-1| or |x| |-x|

OpenStudy (leenathan):

fan?

OpenStudy (leenathan):

if it was minus i think it would be outside the || so i think negative but the ||turns it to positive

OpenStudy (leenathan):

oh sorry i was on peer answer

OpenStudy (leenathan):

the first part i would think you ringt but i might need to te the original question

OpenStudy (leenathan):

post a photo of the qustion

OpenStudy (leenathan):

omfg sorry

OpenStudy (sweetburger):

just substitute the values \[|(-1)^2+5|-4|3(-2)|\]

OpenStudy (leenathan):

|-1^2+5|-4|3-2

OpenStudy (leenathan):

that's what it would be

OpenStudy (sweetburger):

pemdas

OpenStudy (sweetburger):

yes absolute values count as parenthesis

OpenStudy (sweetburger):

start with working inside of the absolute value signs

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