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Mathematics 14 Online
OpenStudy (marcoreus11):

Help

OpenStudy (marcoreus11):

Here

OpenStudy (marcoreus11):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

which problem number?

OpenStudy (marcoreus11):

26

jimthompson5910 (jim_thompson5910):

Ok let's start by labeling the two buses. Let's call them bus A and bus B Bus A will travel 55 mph Bus B will go 45 mph going the opposite direction so far so good?

OpenStudy (marcoreus11):

yes

OpenStudy (marcoreus11):

55A + 45B= 400?

jimthompson5910 (jim_thompson5910):

Close

jimthompson5910 (jim_thompson5910):

Are you familiar with the idea that distance = rate*time ?

OpenStudy (marcoreus11):

no

jimthompson5910 (jim_thompson5910):

"rate" is another term for "speed"

jimthompson5910 (jim_thompson5910):

if you want to know how far you can travel, then multiply the speed by the time eg: if you go 10 mph and travel for 5 hours, then you have gone 50 miles distance = rate*time d = r*t d = 10*5 d = 50 make sense?

OpenStudy (marcoreus11):

yes

jimthompson5910 (jim_thompson5910):

so we don't know the time value. Let's just leave it as t

jimthompson5910 (jim_thompson5910):

for bus A, the speed is 55 mph. We don't know the distance d d = r*t d = 55*t is the equation for bus A. Agreed?

OpenStudy (marcoreus11):

yes

OpenStudy (marcoreus11):

55x4=220

jimthompson5910 (jim_thompson5910):

how are you getting `55x4=220` ?

OpenStudy (marcoreus11):

we are trying to find ou how far they are apart. so 55x4 equal 220 and 45 x 4 equal 180. 180 + 220= 400

jimthompson5910 (jim_thompson5910):

so you did a guess and check?

OpenStudy (marcoreus11):

yes

jimthompson5910 (jim_thompson5910):

ok I'll show you how to do it without guessing

jimthompson5910 (jim_thompson5910):

do you agree so far that the equation for bus A is d = 55t ?

OpenStudy (marcoreus11):

yes

jimthompson5910 (jim_thompson5910):

the equation for bus B would be d = 45t

jimthompson5910 (jim_thompson5910):

The two buses have their distances add to 55t+45t = 100t

jimthompson5910 (jim_thompson5910):

we know the total distance is 400, so 100t = 400 which leads to t = 4

OpenStudy (marcoreus11):

oh i see where u r coming from

OpenStudy (marcoreus11):

can u help me with 27 and 28 too?

jimthompson5910 (jim_thompson5910):

how far did you get with 27

OpenStudy (marcoreus11):

zero

jimthompson5910 (jim_thompson5910):

x is the speed of the slower plane 2x is the speed of the faster plane agreed?

OpenStudy (marcoreus11):

yes

jimthompson5910 (jim_thompson5910):

for the slower plane, the speed is x and the time is 3 hours d = r*t d = x*3 d = 3x for the faster plane, the speed is 3x and the time is also 3 hours d = r*t d = 3x*3 d = 9x

jimthompson5910 (jim_thompson5910):

add the two distances (distance1)+(distance2) = (3x)+(9x) = 3x+9x = 12x

jimthompson5910 (jim_thompson5910):

that total distance 12x is the same as 2700 so, 12x = 2700

OpenStudy (marcoreus11):

225

jimthompson5910 (jim_thompson5910):

x = 225 is the speed of the slower plane. What's the speed of the faster plane?

OpenStudy (marcoreus11):

450

jimthompson5910 (jim_thompson5910):

yes

OpenStudy (marcoreus11):

28?

jimthompson5910 (jim_thompson5910):

show me what you have so far for #28

OpenStudy (marcoreus11):

3x-6=24

OpenStudy (marcoreus11):

x=6

OpenStudy (marcoreus11):

so it would be 18 right?

jimthompson5910 (jim_thompson5910):

if x is the width, then what is the length?

jimthompson5910 (jim_thompson5910):

"the length of the rectangle is 3 cm greater than the width"

OpenStudy (marcoreus11):

oh 3 i thought it said 3 times

OpenStudy (marcoreus11):

i dont know

jimthompson5910 (jim_thompson5910):

width = x length = x+3 agreed?

OpenStudy (marcoreus11):

yes

jimthompson5910 (jim_thompson5910):

perimeter = 2*L + 2*W 24 = 2*(x+3) + 2*x solve for x

OpenStudy (marcoreus11):

5.33

jimthompson5910 (jim_thompson5910):

no

jimthompson5910 (jim_thompson5910):

24 = 2*(x+3) + 2*x 24 = 2x+6+2x 24 = 4x+6 4x+6 = 24 ... ... ... x = ??

OpenStudy (marcoreus11):

4.5

jimthompson5910 (jim_thompson5910):

correct

jimthompson5910 (jim_thompson5910):

width = 4.5 length = ???

OpenStudy (marcoreus11):

7.5

jimthompson5910 (jim_thompson5910):

yes

OpenStudy (marcoreus11):

oh okay thank you so much for the help

jimthompson5910 (jim_thompson5910):

you're welcome

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