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OpenStudy (marcoreus11):
Here
OpenStudy (marcoreus11):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
which problem number?
OpenStudy (marcoreus11):
26
jimthompson5910 (jim_thompson5910):
Ok let's start by labeling the two buses. Let's call them bus A and bus B
Bus A will travel 55 mph
Bus B will go 45 mph going the opposite direction
so far so good?
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OpenStudy (marcoreus11):
yes
OpenStudy (marcoreus11):
55A + 45B= 400?
jimthompson5910 (jim_thompson5910):
Close
jimthompson5910 (jim_thompson5910):
Are you familiar with the idea that
distance = rate*time
?
OpenStudy (marcoreus11):
no
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jimthompson5910 (jim_thompson5910):
"rate" is another term for "speed"
jimthompson5910 (jim_thompson5910):
if you want to know how far you can travel, then multiply the speed by the time
eg:
if you go 10 mph and travel for 5 hours, then you have gone 50 miles
distance = rate*time
d = r*t
d = 10*5
d = 50
make sense?
OpenStudy (marcoreus11):
yes
jimthompson5910 (jim_thompson5910):
so we don't know the time value. Let's just leave it as t
jimthompson5910 (jim_thompson5910):
for bus A, the speed is 55 mph. We don't know the distance d
d = r*t
d = 55*t
is the equation for bus A. Agreed?
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OpenStudy (marcoreus11):
yes
OpenStudy (marcoreus11):
55x4=220
jimthompson5910 (jim_thompson5910):
how are you getting `55x4=220` ?
OpenStudy (marcoreus11):
we are trying to find ou how far they are apart. so 55x4 equal 220 and 45 x 4 equal 180. 180 + 220= 400
jimthompson5910 (jim_thompson5910):
so you did a guess and check?
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OpenStudy (marcoreus11):
yes
jimthompson5910 (jim_thompson5910):
ok I'll show you how to do it without guessing
jimthompson5910 (jim_thompson5910):
do you agree so far that the equation for bus A is d = 55t ?
OpenStudy (marcoreus11):
yes
jimthompson5910 (jim_thompson5910):
the equation for bus B would be d = 45t
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jimthompson5910 (jim_thompson5910):
The two buses have their distances add to 55t+45t = 100t
jimthompson5910 (jim_thompson5910):
we know the total distance is 400, so 100t = 400 which leads to t = 4
OpenStudy (marcoreus11):
oh i see where u r coming from
OpenStudy (marcoreus11):
can u help me with 27 and 28 too?
jimthompson5910 (jim_thompson5910):
how far did you get with 27
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OpenStudy (marcoreus11):
zero
jimthompson5910 (jim_thompson5910):
x is the speed of the slower plane
2x is the speed of the faster plane
agreed?
OpenStudy (marcoreus11):
yes
jimthompson5910 (jim_thompson5910):
for the slower plane, the speed is x and the time is 3 hours
d = r*t
d = x*3
d = 3x
for the faster plane, the speed is 3x and the time is also 3 hours
d = r*t
d = 3x*3
d = 9x
jimthompson5910 (jim_thompson5910):
add the two distances
(distance1)+(distance2) = (3x)+(9x) = 3x+9x = 12x
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jimthompson5910 (jim_thompson5910):
that total distance 12x is the same as 2700
so,
12x = 2700
OpenStudy (marcoreus11):
225
jimthompson5910 (jim_thompson5910):
x = 225 is the speed of the slower plane. What's the speed of the faster plane?
OpenStudy (marcoreus11):
450
jimthompson5910 (jim_thompson5910):
yes
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OpenStudy (marcoreus11):
28?
jimthompson5910 (jim_thompson5910):
show me what you have so far for #28
OpenStudy (marcoreus11):
3x-6=24
OpenStudy (marcoreus11):
x=6
OpenStudy (marcoreus11):
so it would be 18 right?
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jimthompson5910 (jim_thompson5910):
if x is the width, then what is the length?
jimthompson5910 (jim_thompson5910):
"the length of the rectangle is 3 cm greater than the width"
OpenStudy (marcoreus11):
oh 3 i thought it said 3 times
OpenStudy (marcoreus11):
i dont know
jimthompson5910 (jim_thompson5910):
width = x
length = x+3
agreed?
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OpenStudy (marcoreus11):
yes
jimthompson5910 (jim_thompson5910):
perimeter = 2*L + 2*W
24 = 2*(x+3) + 2*x
solve for x