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Which value for x makes the open sentence true? 7 + 6 • x = 4^2 + x^2 a) 5 b) 4 c) 3 d) 2
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Change it to standard form first ax^2 + bx + c = 0 x^2 - 6x + 9 = 0 can you factor that now
@AloneS
Recall the zero-product property ab=0 if and only if a=0 or b=0.
But there is no a or b.... there's x. I'm confused.
The "a or b" stands for any variable :-)
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Do you see how DanJS got x^2 -6x +9 = 0?
Nope, no idea.
$$7 + 6 • x = 4^2 + x^2$$ $$7 + 6 • x -7-6•x= 4^2 + x^2-7-6•x$$
Subtract 7 and 6•x from both sides.
So then, on the left side of the equal sign, would it be x^2?
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Nope, it would be 0.
Alright I think I can figure it out now. Thanks.
Thanks for trying :-)
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