@kevin HELP
Hey i need help with this i was thinking to create a new function let me know your thoughts i will provide my "new function" in the next reply
I tried.. Sorry I'm sleepy..
\[l(x) = 20(1.2^(x-1))\] would that work to predict ?
it is fine Thanks for helping tho
@IrishBoy123
@kittiwitti1
Let the out final function be f(x). So, at f(1), 1 square foot, he was 20 strawberries. f(x) = 20 + ..... And for every square foot more, we will add that to f(x) to figure out the amount of strawberries at x square feet. f(x) = 20 + 1.2(x-1).... f(1) = 20 + 1.2(1-1) = 20 That's what I got..
why did you added 20 shouldn't it be multiplied?
NOTE: Function a(x) is = \[1.2^{x-1}\]
I do know that. You're just plugging in values as is.
It's geometry series, you can find how many strowberries are using formula : 20 x (2^15 - 1)/ (2 - 1)
can you provide explanation i need to add it in the answer
Original formula is a x (r^n - 1) / (r - ) a = first sequence r = ratio n = amount of sequence As you can see the first strawberries planted are 20 fruits, it's become the first sequence. The ratio, you can find it in the question -> a(x) = 1.2^x-1 with 2 is a ratio.
it's a x (r^n - 1) / (r - 1)
badly scripted question though IMHO taking it literally, you really should apply the exponential growth to all squares once you add one; and in practise it presumably models the attractiveness of the entire plot to pollinators blah blah so that would make sense.
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