Solve for X. (2x+5)(6x-1)=120
(2x + 5)(6x - 1) = 120 12x^2 - 2x + 30x - 5 = 120 12x^2 + 28x - 125 = 0 x = [-28 +/- sqrt(784 + 4*12*125)]/24 x = [-28 +/- sqrt(6784)]/24 x = [-28 +/- 8sqrt(106)]/24 x = [-7 +/- 2sqrt(106)]/6 Though they are ugly, these are your two solutions to the original equation.
can u do it take a pic of it and attach it so i see what it is meaning i dont understand this
no because im on my computer so, go on google and search tiger algebra and plug it in on there it should give you a better explanation
this makes no sense
Andrew, do you know how to multiply the equation? (2x+5)(6x-1)=120
no its been too long
That would be the first step. Taylor0402 already multiplied it for you and it is 12x^2 - 2x + 30x - 5 = 120
Andrew if it has been a long time since you have done algebra, are you even ready to be doing this type of math?
i am doin this to help my gf. My memory loss is whats making it harder to remember its been 3 years since i did this that i can remember and am wanting to learn it again so i can help her with her homework and get better at this again. i had straight a's when i had done it but yeah.
Okay, the next step is to get the equation 12x^2 - 2x + 30x - 5 = 120 and add the terms so you can have an equation with just 3 terms. Can you do that?
other subjects from this i know still because i use it everyday
Can you do what I asked you in the posting above?
12x^2-2x+30x-125=0?
Okay but you have to combine the -2x with +30x
oh yeah 12x^2+28-125=0
Now you solve the equation using the Quadratic Formula
The "a" term is 12 The "b" term is 28 The "c" term is -125
\[\frac{ -28+/-\sqrt{28^2-4(12x-125)} }{ 2a }\]
yes?
That should be 28^2 -4*12*-125 and 2a should be 2* 12 or 24
use equation button on here please so i can understand
\[4 a c = 4*12*-125\]
It is NOT 4 *(12 -125)
ok
and 2a = 2 * 12 or 24
can u make the whole thing i did with the fixes so i see how it should be?
\[x = (-28 ± \sqrt{28² - 4*12*-125} ) ÷ 2*12\]
\[x = (-28 ±\sqrt{784 +6,000} ) ÷ 24\]
ok
Okay then
what next
\[x = (-28 ±\sqrt{6,784} ) ÷ 24\]
Taylor 0402 pretty much did what I just did so look for that solution almost at the top of this posting.
thanks
now i understand
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