Need explanations: When a car makes an emergency stop on dry pavement, it leaves skid marks on the pavement. The speed S, in miles per hour, of the car when the brakes were applied is related to the length L, in feet, of the skid mark. The relationship is S(L) = 5.05 sqrt of L (a) Use functional notation to express the speed at which the skid mark will be 70 feet. s(____) Calculate that speed. (Round your answer to two decimal places.) ___mph
skid mark = L = 70 feet S(L) = 5.05 sqrt(70) |dw:1473464768595:dw|
mph
Thank you so much! This is the last question they ask over it, I'm leaning towards c?? (b) Explain in practical terms the meaning of S(100). S(100) is the speed, in miles per hour, at which an emergency stop will leave a skid mark of 100 feet. S(100) is the speed, in meters per second, at which an emergency stop will leave a skid mark of 100 meters. S(100) is the time a car has been traveling, in hours, at which an emergency stop will leave a skid mark of 100 feet. S(100) is the length of the skid mark, in feet, caused by an emergency stop when a car is traveling 100 miles per hour. S(100) is the length of the skid mark, in feet, caused by an emergency stop when a car has traveled 100 miles.
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