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Mathematics 13 Online
OpenStudy (markchernioglo):

Please Help! Write a real world situation that could be modeled by |x-14|=3

OpenStudy (zzr0ck3r):

Suppose you have something that you want to be 14 inches plus or minus 3.

OpenStudy (markchernioglo):

I found x=17 and x=11. I just can't figure out how I can use these problems.

OpenStudy (markchernioglo):

@zzr0ck3r so do you know by this question if I had to solve for x?

OpenStudy (markchernioglo):

@brainzonly

OpenStudy (brainzonly):

I'm here

OpenStudy (markchernioglo):

Hello, do you happen to understand this?

OpenStudy (markchernioglo):

zz seems to be afk

OpenStudy (brainzonly):

sort of...

OpenStudy (brainzonly):

my internet is off and on I might lose it completely in a few minutes :(

OpenStudy (markchernioglo):

Oh, its fine if you cant answer it. No worries

OpenStudy (brainzonly):

x=17? are there any options

OpenStudy (markchernioglo):

X=17 is one and x=11

OpenStudy (brainzonly):

?

OpenStudy (brainzonly):

u mean x=17 is option 1?

OpenStudy (markchernioglo):

I have two options, there is not 1. I solved for x in |x-14|=3

OpenStudy (markchernioglo):

so pretty much |x-14|=3 and |x-14|=-3 I added 14+3, and then on second one i added 14+-3. I got x=17, x=11

OpenStudy (brainzonly):

I think its x=17. you add 14 to both sides to undo the "-" otherwise it will become |x-28|=-11!

OpenStudy (markchernioglo):

Idk lol

OpenStudy (markchernioglo):

Alright it probably is, I will keep that in mind. Whenever zz is back I will just make sure. Thanks bro!

OpenStudy (brainzonly):

x=17 ok? see ya

OpenStudy (markchernioglo):

k thanks, cya

OpenStudy (markchernioglo):

What I do not understand is how to put this problem into real world problem.

OpenStudy (markchernioglo):

*situation

OpenStudy (markchernioglo):

Ok I got it. I put There are 14 balls in a box, there could be either 3 more or 3 less balls in the box. So x=17 or x=11.

OpenStudy (zzr0ck3r):

\(|x|=a\) means \(x=a \) or \(x=-a\) So we have \(|x-14|=3\) means \(x-14=3\) and \(x-14=-3\) So we have \(x=17\) and \(x=11\)

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