Question

Next question @Loser66

Answer 1

I'm gonna go through my steps, it just helps me think. Can you just lemme know if you see a problem?

Answer 2

Go ahead.

Answer 3

So for f(x) = -1/5x - 1
Switch roles: -1/5x = f^-1(x) - 1
Do I add 1 on both sides?

Answer 4

Sorry switching roles would be
1/5x = -f^-1(x) - 1

Answer 5

Nope, just switch the role for x and f(x) only, the numbers stay!!

Answer 6

ohhhh, so what would that be? sorry I suckkkk at math.

Answer 7

f(x) =(-1/5) x-1
step 1, switch the roles
\(x=(-1/5) f^{-1}(x) -1 \)

Answer 8

ok? Numbers stay as they are.

Answer 9

Oh okay.

Answer 10

So now do I add 1 to each side?

Answer 11

yup

Answer 12

So 1 + x = (-1/5)f^-1(x)
I suppose I do something with the -1/5 right?

Answer 13

multiply both sides by 5?

Answer 14

(-5) not 5

Answer 15

ok so
-5 - 5x = f^-1(x)?

Answer 16

Bingo

Answer 17

so f^-1(x) = -5x -5
go on to graphing,
do I just do the same thing you did with the whole -5(0) - 5 = -5
-5(1) - 5 = 0?

Answer 18

yes.

Answer 19

I feel like I did something wrong with the graphing, so would the two points be (0,-5) and (1,0)?

Answer 20

You are perfectly correct.

Answer 21

good

Answer 22

When I have mathway.com graph it for me it shows something different

Answer 23

The points on their graph are (-5, 0) and (-1, 0)

Answer 24

oh, yes!! my bad

Answer 25

(-5)*1 -5 = -10
not 0
but if you use (-5)*(-1) -5 =0

Answer 26

ha!! you see. I am wrong also. So, no need to feel bad on math.

Answer 27

so one of the points would be (1, -10)?

Answer 28

yes. :)

Answer 29

Okay, thank you so much! Could you possibly check my answer to the next question just to make sure I have it down? I won't need to go over the steps, just show you my answer when I get it

Answer 30

sure