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Find an equation of the line that is tangent to the graph of f and parallel to the given line:
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\[Function: f(x)=\frac{ 1 }{ \sqrt{x} }\]
\[Line:x+2y-6=0\]
First find the slope of the given line. Then find the derivative of f(x), and set it equal to that slope, solve for x. Then plug x back into f(x) and solve. Then you can make the equation of the line, using the slope from the first step, and the point (x, f(x))
yeah Im having trouble setting it equal to the slope
Show work.
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\[x ^{-1/2}=\frac{ -x }{ 2 }\]
that's the farthest I've gotten
That's... not close. You haven't even found the derivative of f(x). I've no idea what you did. Follow the steps in the order I gave. Show work.
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