Question

Find an equation of the line that is tangent to the graph of f and parallel to the given line:

Answer 1

\[Function: f(x)=\frac{ 1 }{ \sqrt{x} }\]

Answer 2

\[Line:x+2y-6=0\]

Answer 3

First find the slope of the given line.

Then find the derivative of f(x), and set it equal to that slope, solve for x.

Then plug x back into f(x) and solve.

Then you can make the equation of the line, using the slope from the first step, and the point (x, f(x))

Answer 4

yeah Im having trouble setting it equal to the slope

Answer 5

Show work.

Answer 6

\[x ^{-1/2}=\frac{ -x }{ 2 }\]

Answer 7

that's the farthest I've gotten

Answer 8

That's... not close. You haven't even found the derivative of f(x). I've no idea what you did.

Follow the steps in the order I gave. Show work.